Erika had
45 as many sweets as Lee. Lee had
34 as many sweets as Carl. If Carl had 72 more sweets than Erika, find the total number of sweets that was shared among these 3 children at first.
Erika |
Lee |
Carl |
4x3 |
5x3 |
|
|
3x5 |
4x5 |
12 u |
15 u |
20 u |
Lee is the repeated identity.
LCM of 5 and 3 = 15
Number of more sweets that Carl had more than Erika
= 20 u - 12 u
= 8 u
8 u = 72
1 u = 72 ÷ 8 = 9
Total number of sweets
= 12 u + 15 u + 20 u
= 47 u
= 47 x 9
= 423
Answer(s): 423