Lynn had
45 as many mochi balls as Tommy. Tommy had
45 as many mochi balls as Daniel. If Daniel had 27 more mochi balls than Lynn, find the total number of mochi balls that was shared among these 3 children at first.
Lynn |
Tommy |
Daniel |
4x4 |
5x4 |
|
|
4x5 |
5x5 |
16 u |
20 u |
25 u |
Tommy is the repeated identity.
LCM of 5 and 4 = 20
Number of more mochi balls that Daniel had more than Lynn
= 25 u - 16 u
= 9 u
9 u = 27
1 u = 27 ÷ 9 = 3
Total number of mochi balls
= 16 u + 20 u + 25 u
= 61 u
= 61 x 3
= 183
Answer(s): 183