Hazel had
47 as many candy canes as Jenson. Jenson had
45 as many candy canes as Albert. If Albert had 76 more candy canes than Hazel, find the total number of candy canes that was shared among these 3 children at first.
Hazel |
Jenson |
Albert |
4x4 |
7x4 |
|
|
4x7 |
5x7 |
16 u |
28 u |
35 u |
Jenson is the repeated identity.
LCM of 7 and 4 = 28
Number of more candy canes that Albert had more than Hazel
= 35 u - 16 u
= 19 u
19 u = 76
1 u = 76 ÷ 19 = 4
Total number of candy canes
= 16 u + 28 u + 35 u
= 79 u
= 79 x 4
= 316
Answer(s): 316