Betty had
45 as many lollipops as John. John had
38 as many lollipops as Cole. If Cole had 168 more lollipops than Betty, find the total number of lollipops that was shared among these 3 children at first.
Betty |
John |
Cole |
4x3 |
5x3 |
|
|
3x5 |
8x5 |
12 u |
15 u |
40 u |
John is the repeated identity.
LCM of 5 and 3 = 15
Number of more lollipops that Cole had more than Betty
= 40 u - 12 u
= 28 u
28 u = 168
1 u = 168 ÷ 28 = 6
Total number of lollipops
= 12 u + 15 u + 40 u
= 67 u
= 67 x 6
= 402
Answer(s): 402