Usha had
45 as many caramel apples as Albert. Albert had
34 as many caramel apples as Tommy. If Tommy had 64 more caramel apples than Usha, find the total number of caramel apples that was shared among these 3 children at first.
Usha |
Albert |
Tommy |
4x3 |
5x3 |
|
|
3x5 |
4x5 |
12 u |
15 u |
20 u |
Albert is the repeated identity.
LCM of 5 and 3 = 15
Number of more caramel apples that Tommy had more than Usha
= 20 u - 12 u
= 8 u
8 u = 64
1 u = 64 ÷ 8 = 8
Total number of caramel apples
= 12 u + 15 u + 20 u
= 47 u
= 47 x 8
= 376
Answer(s): 376