Lynn had
45 as many candy canes as Michael. Michael had
38 as many candy canes as Tommy. If Tommy had 196 more candy canes than Lynn, find the total number of candy canes that was shared among these 3 children at first.
| Lynn |
Michael |
Tommy |
| 4x3 |
5x3 |
|
| |
3x5 |
8x5 |
| 12 u |
15 u |
40 u |
Michael is the repeated identity.
LCM of 5 and 3 = 15
Number of more candy canes that Tommy had more than Lynn
= 40 u - 12 u
= 28 u
28 u = 196
1 u = 196 ÷ 28 = 7
Total number of candy canes
= 12 u + 15 u + 40 u
= 67 u
= 67 x 7
= 469
Answer(s): 469
