Jade had
45 as many candy canes as Glen. Glen had
45 as many candy canes as Justin. If Justin had 108 more candy canes than Jade, find the total number of candy canes that was shared among these 3 children at first.
Jade |
Glen |
Justin |
4x4 |
5x4 |
|
|
4x5 |
5x5 |
16 u |
20 u |
25 u |
Glen is the repeated identity.
LCM of 5 and 4 = 20
Number of more candy canes that Justin had more than Jade
= 25 u - 16 u
= 9 u
9 u = 108
1 u = 108 ÷ 9 = 12
Total number of candy canes
= 16 u + 20 u + 25 u
= 61 u
= 61 x 12
= 732
Answer(s): 732