Tammy had
45 as many caramel apples as David. David had
38 as many caramel apples as Daniel. If Daniel had 308 more caramel apples than Tammy, find the total number of caramel apples that was shared among these 3 children at first.
Tammy |
David |
Daniel |
4x3 |
5x3 |
|
|
3x5 |
8x5 |
12 u |
15 u |
40 u |
David is the repeated identity.
LCM of 5 and 3 = 15
Number of more caramel apples that Daniel had more than Tammy
= 40 u - 12 u
= 28 u
28 u = 308
1 u = 308 ÷ 28 = 11
Total number of caramel apples
= 12 u + 15 u + 40 u
= 67 u
= 67 x 11
= 737
Answer(s): 737