Pamela had
47 as many caramel apples as Flynn. Flynn had
35 as many caramel apples as Tommy. If Tommy had 46 more caramel apples than Pamela, find the total number of caramel apples that was shared among these 3 children at first.
| Pamela |
Flynn |
Tommy |
| 4x3 |
7x3 |
|
| |
3x7 |
5x7 |
| 12 u |
21 u |
35 u |
Flynn is the repeated identity.
LCM of 7 and 3 = 21
Number of more caramel apples that Tommy had more than Pamela
= 35 u - 12 u
= 23 u
23 u = 46
1 u = 46 ÷ 23 = 2
Total number of caramel apples
= 12 u + 21 u + 35 u
= 68 u
= 68 x 2
= 136
Answer(s): 136
