Julie had
57 as many candy canes as Valen. Valen had
35 as many candy canes as Fabian. If Fabian had 240 more candy canes than Julie, find the total number of candy canes that was shared among these 3 children at first.
| Julie |
Valen |
Fabian |
| 5x3 |
7x3 |
|
| |
3x7 |
5x7 |
| 15 u |
21 u |
35 u |
Valen is the repeated identity.
LCM of 7 and 3 = 21
Number of more candy canes that Fabian had more than Julie
= 35 u - 15 u
= 20 u
20 u = 240
1 u = 240 ÷ 20 = 12
Total number of candy canes
= 15 u + 21 u + 35 u
= 71 u
= 71 x 12
= 852
Answer(s): 852
