Xuan had
45 as many caramel apples as Billy. Billy had
45 as many caramel apples as Sam. If Sam had 81 more caramel apples than Xuan, find the total number of caramel apples that was shared among these 3 children at first.
Xuan |
Billy |
Sam |
4x4 |
5x4 |
|
|
4x5 |
5x5 |
16 u |
20 u |
25 u |
Billy is the repeated identity.
LCM of 5 and 4 = 20
Number of more caramel apples that Sam had more than Xuan
= 25 u - 16 u
= 9 u
9 u = 81
1 u = 81 ÷ 9 = 9
Total number of caramel apples
= 16 u + 20 u + 25 u
= 61 u
= 61 x 9
= 549
Answer(s): 549