Shannon had
58 as many chocolate bars as Charlie. Charlie had
34 as many chocolate bars as Luis. If Luis had 102 more chocolate bars than Shannon, find the total number of chocolate bars that was shared among these 3 children at first.
Shannon |
Charlie |
Luis |
5x3 |
8x3 |
|
|
3x8 |
4x8 |
15 u |
24 u |
32 u |
Charlie is the repeated identity.
LCM of 8 and 3 = 24
Number of more chocolate bars that Luis had more than Shannon
= 32 u - 15 u
= 17 u
17 u = 102
1 u = 102 ÷ 17 = 6
Total number of chocolate bars
= 15 u + 24 u + 32 u
= 71 u
= 71 x 6
= 426
Answer(s): 426