Fiona had
47 as many lollipops as Xavier. Xavier had
34 as many lollipops as Vincent. If Vincent had 128 more lollipops than Fiona, find the total number of lollipops that was shared among these 3 children at first.
| Fiona |
Xavier |
Vincent |
| 4x3 |
7x3 |
|
| |
3x7 |
4x7 |
| 12 u |
21 u |
28 u |
Xavier is the repeated identity.
LCM of 7 and 3 = 21
Number of more lollipops that Vincent had more than Fiona
= 28 u - 12 u
= 16 u
16 u = 128
1 u = 128 ÷ 16 = 8
Total number of lollipops
= 12 u + 21 u + 28 u
= 61 u
= 61 x 8
= 488
Answer(s): 488
