Mary had
45 as many candy canes as Flynn. Flynn had
37 as many candy canes as Tommy. If Tommy had 161 more candy canes than Mary, find the total number of candy canes that was shared among these 3 children at first.
| Mary |
Flynn |
Tommy |
| 4x3 |
5x3 |
|
| |
3x5 |
7x5 |
| 12 u |
15 u |
35 u |
Flynn is the repeated identity.
LCM of 5 and 3 = 15
Number of more candy canes that Tommy had more than Mary
= 35 u - 12 u
= 23 u
23 u = 161
1 u = 161 ÷ 23 = 7
Total number of candy canes
= 12 u + 15 u + 35 u
= 62 u
= 62 x 7
= 434
Answer(s): 434
