Jade had
45 as many candy canes as Howard. Howard had
47 as many candy canes as Japheth. If Japheth had 95 more candy canes than Jade, find the total number of candy canes that was shared among these 3 children at first.
Jade |
Howard |
Japheth |
4x4 |
5x4 |
|
|
4x5 |
7x5 |
16 u |
20 u |
35 u |
Howard is the repeated identity.
LCM of 5 and 4 = 20
Number of more candy canes that Japheth had more than Jade
= 35 u - 16 u
= 19 u
19 u = 95
1 u = 95 ÷ 19 = 5
Total number of candy canes
= 16 u + 20 u + 35 u
= 71 u
= 71 x 5
= 355
Answer(s): 355