Julie had
45 as many lollipops as Archie. Archie had
38 as many lollipops as Mark. If Mark had 84 more lollipops than Julie, find the total number of lollipops that was shared among these 3 children at first.
Julie |
Archie |
Mark |
4x3 |
5x3 |
|
|
3x5 |
8x5 |
12 u |
15 u |
40 u |
Archie is the repeated identity.
LCM of 5 and 3 = 15
Number of more lollipops that Mark had more than Julie
= 40 u - 12 u
= 28 u
28 u = 84
1 u = 84 ÷ 28 = 3
Total number of lollipops
= 12 u + 15 u + 40 u
= 67 u
= 67 x 3
= 201
Answer(s): 201