Pamela had
67 as many lollipops as Cole. Cole had
35 as many lollipops as Albert. If Albert had 136 more lollipops than Pamela, find the total number of lollipops that was shared among these 3 children at first.
Pamela |
Cole |
Albert |
6x3 |
7x3 |
|
|
3x7 |
5x7 |
18 u |
21 u |
35 u |
Cole is the repeated identity.
LCM of 7 and 3 = 21
Number of more lollipops that Albert had more than Pamela
= 35 u - 18 u
= 17 u
17 u = 136
1 u = 136 ÷ 17 = 8
Total number of lollipops
= 18 u + 21 u + 35 u
= 74 u
= 74 x 8
= 592
Answer(s): 592