At the bowling alley, there were 16 as many men as women and 23 as many children as adults. If there were 88 more children than men at the bowling alley, find the total number of people at the bowling alley.
| Children |
Adults |
Total |
| 2x7 |
3x7 |
5x7 |
| |
Men |
Women |
|
| |
1x3 |
6x3 |
|
| 14 u |
3 u |
18 u |
35 u |
Number of adults is the combined repeated identity. Make the number of adults the same. LCM of 7 and 3 is 21.
Number of more children than men
= 14 u - 3 u
= 11 u
11 u = 88
1 u = 88 ÷ 11 = 8
Total number of people
= 35 u
= 35 x 8
= 280
Answer(s): 280
