At the bowling alley, there were 15 as many men as women and 23 as many children as adults. If there were 9 more children than men at the bowling alley, find the total number of people at the bowling alley.
| Children |
Adults |
Total |
| 2x2 |
3x2 |
5x2 |
| |
Men |
Women |
|
| |
1x1 |
5x1 |
|
| 4 u |
1 u |
5 u |
10 u |
Number of adults is the combined repeated identity. Make the number of adults the same. LCM of 6 and 3 is 6.
Number of more children than men
= 4 u - 1 u
= 3 u
3 u = 9
1 u = 9 ÷ 3 = 3
Total number of people
= 10 u
= 10 x 3
= 30
Answer(s): 30
