A fruit-seller sold
47 of his lemons in the morning and
59 of his remaining lemons in the afternoon. If he had 28 lemons at the end of the day, find the total number of lemons he had at first.
| Morning |
Remaining lemons |
Total |
| 4x3 |
3x3 |
7x3 |
| |
Afternoon |
Left |
|
| |
5 |
4 |
|
| 12 u |
5 u |
4 u |
21 u |
Fraction of the lemons not sold in the morning
= 1 - 47
= 37
Number of lemons left = 4 u
4 u = 28
1 u = 28 ÷ 4 = 7
Total number of lemons
= 21 u
= 21 x 7
= 147
Answer(s): 147
