A fruit-seller sold
47 of his pears in the morning and
49 of his remaining pears in the afternoon. If he had 40 pears at the end of the day, find the total number of pears he had at first.
| Morning |
Remaining pears |
Total |
| 4x3 |
3x3 |
7x3 |
| |
Afternoon |
Left |
|
| |
4 |
5 |
|
| 12 u |
4 u |
5 u |
21 u |
Fraction of the pears not sold in the morning
= 1 - 47
= 37
Number of pears left = 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Total number of pears
= 21 u
= 21 x 8
= 168
Answer(s): 168
