A fruit-seller sold
56 of his kiwis in the morning and
38 of his remaining kiwis in the afternoon. If he had 40 kiwis at the end of the day, find the total number of kiwis he had at first.
| Morning |
Remaining kiwis |
Total |
| 5x8 |
1x8 |
6x8 |
| |
Afternoon |
Left |
|
| |
3 |
5 |
|
| 40 u |
3 u |
5 u |
48 u |
Fraction of the kiwis not sold in the morning
= 1 - 56
= 16
Number of kiwis left = 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Total number of kiwis
= 48 u
= 48 x 8
= 384
Answer(s): 384
