A fruit-seller sold
56 of his pears in the morning and
38 of his remaining pears in the afternoon. If he had 25 pears at the end of the day, find the total number of pears he had at first.
| Morning |
Remaining pears |
Total |
| 5x8 |
1x8 |
6x8 |
| |
Afternoon |
Left |
|
| |
3 |
5 |
|
| 40 u |
3 u |
5 u |
48 u |
Fraction of the pears not sold in the morning
= 1 - 56
= 16
Number of pears left = 5 u
5 u = 25
1 u = 25 ÷ 5 = 5
Total number of pears
= 48 u
= 48 x 5
= 240
Answer(s): 240
