A fruit-seller sold
34 of his mangoes in the morning and
57 of his remaining mangoes in the afternoon. If he had 40 mangoes at the end of the day, find the total number of mangoes he had at first.
| Morning |
Remaining mangoes |
Total |
| 3x7 |
1x7 |
4x7 |
| |
Afternoon |
Left |
|
| |
5 |
2 |
|
| 21 u |
5 u |
2 u |
28 u |
Fraction of the mangoes not sold in the morning
= 1 - 34
= 14
Number of mangoes left = 2 u
2 u = 40
1 u = 40 ÷ 2 = 20
Total number of mangoes
= 28 u
= 28 x 20
= 560
Answer(s): 560
