A fruit-seller sold
56 of his lemons in the morning and
58 of his remaining lemons in the afternoon. If he had 36 lemons at the end of the day, find the total number of lemons he had at first.
| Morning |
Remaining lemons |
Total |
| 5x8 |
1x8 |
6x8 |
| |
Afternoon |
Left |
|
| |
5 |
3 |
|
| 40 u |
5 u |
3 u |
48 u |
Fraction of the lemons not sold in the morning
= 1 - 56
= 16
Number of lemons left = 3 u
3 u = 36
1 u = 36 ÷ 3 = 12
Total number of lemons
= 48 u
= 48 x 12
= 576
Answer(s): 576
