A fruit-seller sold
23 of his peaches in the morning and
59 of his remaining peaches in the afternoon. If he had 40 peaches at the end of the day, find the total number of peaches he had at first.
| Morning |
Remaining peaches |
Total |
| 2x9 |
1x9 |
3x9 |
| |
Afternoon |
Left |
|
| |
5 |
4 |
|
| 18 u |
5 u |
4 u |
27 u |
Fraction of the peaches not sold in the morning
= 1 - 23
= 13
Number of peaches left = 4 u
4 u = 40
1 u = 40 ÷ 4 = 10
Total number of peaches
= 27 u
= 27 x 10
= 270
Answer(s): 270
