A fruit-seller sold
56 of his pomegranates in the morning and
57 of his remaining pomegranates in the afternoon. If he had 28 pomegranates at the end of the day, find the total number of pomegranates he had at first.
| Morning |
Remaining pomegranates |
Total |
| 5x7 |
1x7 |
6x7 |
| |
Afternoon |
Left |
|
| |
5 |
2 |
|
| 35 u |
5 u |
2 u |
42 u |
Fraction of the pomegranates not sold in the morning
= 1 - 56
= 16
Number of pomegranates left = 2 u
2 u = 28
1 u = 28 ÷ 2 = 14
Total number of pomegranates
= 42 u
= 42 x 14
= 588
Answer(s): 588
