A fruit-seller sold
56 of his mangoes in the morning and
49 of his remaining mangoes in the afternoon. If he had 35 mangoes at the end of the day, find the total number of mangoes he had at first.
| Morning |
Remaining mangoes |
Total |
| 5x9 |
1x9 |
6x9 |
| |
Afternoon |
Left |
|
| |
4 |
5 |
|
| 45 u |
4 u |
5 u |
54 u |
Fraction of the mangoes not sold in the morning
= 1 - 56
= 16
Number of mangoes left = 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Total number of mangoes
= 54 u
= 54 x 7
= 378
Answer(s): 378
