Two rectangles S and T, not drawn to scale, overlap at U. U is the shaded area which is
12 of Rectangle S and
14 of Rectangle T. If the length of Rectangle S is 11 cm and its breadth is 4 cm, what is the area of the unshaded part of rectangles S and T?
| |
S |
T |
Difference |
| Total areas |
2 u |
4 u |
2 u |
| Shaded part |
- 1 u |
- 1 u |
|
| Unshaded parts |
1 u |
3 u |
2 u |
The overlapping shaded part of rectangles S and T is the same.
Area of Rectangle S
= 11 x 4
= 44 cm
2 Area of Rectangle S = 2 u
Area of Rectangle T = 4 u
2 u = 44
1 u = 44 ÷ 2 = 22
Area of unshaded parts of rectangles S and T
= 1 u + 3 u
= 4 u
= 4 x 22
= 88 cm
2 Answer(s): 88 cm
2 
