Two rectangles Y and Z, not drawn to scale, overlap at A. A is the shaded area which is
12 of Rectangle Y and
17 of Rectangle Z. If the length of Rectangle Y is 14 cm and its breadth is 4 cm, what is the area of the unshaded part of rectangles Y and Z?
|
Y |
Z |
Difference |
Total areas |
2 u |
7 u |
5 u |
Shaded part |
- 1 u |
- 1 u |
|
Unshaded parts |
1 u |
6 u |
5 u |
The overlapping shaded part of rectangles Y and Z is the same.
Area of Rectangle Y
= 14 x 4
= 56 cm
2 Area of Rectangle Y = 2 u
Area of Rectangle Z = 7 u
2 u = 56
1 u = 56 ÷ 2 = 28
Area of unshaded parts of rectangles Y and Z
= 1 u + 6 u
= 7 u
= 7 x 28
= 196 cm
2 Answer(s): 196 cm
2