Two rectangles N and P, not drawn to scale, overlap at Q. Q is the shaded area which is
16 of Rectangle N and
19 of Rectangle P. If the length of Rectangle N is 6 cm and its breadth is 5 cm, what is the area of the unshaded part of rectangles N and P?
|
N |
P |
Difference |
Total areas |
6 u |
9 u |
3 u |
Shaded part |
- 1 u |
- 1 u |
|
Unshaded parts |
5 u |
8 u |
3 u |
The overlapping shaded part of rectangles N and P is the same.
Area of Rectangle N
= 6 x 5
= 30 cm
2 Area of Rectangle N = 6 u
Area of Rectangle P = 9 u
6 u = 30
1 u = 30 ÷ 6 = 5
Area of unshaded parts of rectangles N and P
= 5 u + 8 u
= 13 u
= 13 x 5
= 65 cm
2 Answer(s): 65 cm
2