Two rectangles D and E, not drawn to scale, overlap at F. F is the shaded area which is
12 of Rectangle D and
16 of Rectangle E. If the length of Rectangle D is 14 m and its breadth is 4 m, what is the area of the unshaded part of rectangles D and E?
| |
D |
E |
Difference |
| Total areas |
2 u |
6 u |
4 u |
| Shaded part |
- 1 u |
- 1 u |
|
| Unshaded parts |
1 u |
5 u |
4 u |
The overlapping shaded part of rectangles D and E is the same.
Area of Rectangle D
= 14 x 4
= 56 m
2 Area of Rectangle D = 2 u
Area of Rectangle E = 6 u
2 u = 56
1 u = 56 ÷ 2 = 28
Area of unshaded parts of rectangles D and E
= 1 u + 5 u
= 6 u
= 6 x 28
= 168 m
2 Answer(s): 168 m
2 
