Two rectangles S and T, not drawn to scale, overlap at U. U is the shaded area which is
12 of Rectangle S and
16 of Rectangle T. If the length of Rectangle S is 15 m and its breadth is 6 m, what is the area of the unshaded part of rectangles S and T?
|
S |
T |
Difference |
Total areas |
2 u |
6 u |
4 u |
Shaded part |
- 1 u |
- 1 u |
|
Unshaded parts |
1 u |
5 u |
4 u |
The overlapping shaded part of rectangles S and T is the same.
Area of Rectangle S
= 15 x 6
= 90 m
2 Area of Rectangle S = 2 u
Area of Rectangle T = 6 u
2 u = 90
1 u = 90 ÷ 2 = 45
Area of unshaded parts of rectangles S and T
= 1 u + 5 u
= 6 u
= 6 x 45
= 270 m
2 Answer(s): 270 m
2