Two rectangles N and P, not drawn to scale, overlap at Q. Q is the shaded area which is
12 of Rectangle N and
16 of Rectangle P. If the length of Rectangle N is 12 cm and its breadth is 6 cm, what is the area of the unshaded part of rectangles N and P?
|
N |
P |
Difference |
Total areas |
2 u |
6 u |
4 u |
Shaded part |
- 1 u |
- 1 u |
|
Unshaded parts |
1 u |
5 u |
4 u |
The overlapping shaded part of rectangles N and P is the same.
Area of Rectangle N
= 12 x 6
= 72 cm
2 Area of Rectangle N = 2 u
Area of Rectangle P = 6 u
2 u = 72
1 u = 72 ÷ 2 = 36
Area of unshaded parts of rectangles N and P
= 1 u + 5 u
= 6 u
= 6 x 36
= 216 cm
2 Answer(s): 216 cm
2