Two rectangles S and T, not drawn to scale, overlap at U. U is the shaded area which is
12 of Rectangle S and
15 of Rectangle T. If the length of Rectangle S is 11 m and its breadth is 6 m, what is the area of the unshaded part of rectangles S and T?
| |
S |
T |
Difference |
| Total areas |
2 u |
5 u |
3 u |
| Shaded part |
- 1 u |
- 1 u |
|
| Unshaded parts |
1 u |
4 u |
3 u |
The overlapping shaded part of rectangles S and T is the same.
Area of Rectangle S
= 11 x 6
= 66 m
2 Area of Rectangle S = 2 u
Area of Rectangle T = 5 u
2 u = 66
1 u = 66 ÷ 2 = 33
Area of unshaded parts of rectangles S and T
= 1 u + 4 u
= 5 u
= 5 x 33
= 165 m
2 Answer(s): 165 m
2 
