Two rectangles R and S, not drawn to scale, overlap at T. T is the shaded area which is
17 of Rectangle R and
110 of Rectangle S. If the length of Rectangle R is 14 cm and its breadth is 4 cm, what is the area of the unshaded part of rectangles R and S?
| |
R |
S |
Difference |
| Total areas |
7 u |
10 u |
3 u |
| Shaded part |
- 1 u |
- 1 u |
|
| Unshaded parts |
6 u |
9 u |
3 u |
The overlapping shaded part of rectangles R and S is the same.
Area of Rectangle R
= 14 x 4
= 56 cm
2 Area of Rectangle R = 7 u
Area of Rectangle S = 10 u
7 u = 56
1 u = 56 ÷ 7 = 8
Area of unshaded parts of rectangles R and S
= 6 u + 9 u
= 15 u
= 15 x 8
= 120 cm
2 Answer(s): 120 cm
2 
