411 of a metallic rod was painted blue.
511 of it was painted red. The remaining 26 cm of the metallic rod was painted silver.
- What fraction of the metallic rod was painted silver?
- What was the length of the metallic rod?
(a)
Fraction of the metallic rod painted silver
= 1 -
411 -
511=
211(b)
Length of silver part of the metallic rod = 2 u
2 u = 26
1 u = 26 ÷ 2 = 13
Length of the metallic rod
= 11 u
= 11 x 13
= 143 cm
Answer(s): (a)
211; (b) 143 cm