111 of a metallic rod was painted gold.
811 of it was painted red. The remaining 38 cm of the metallic rod was painted brown.
- What fraction of the metallic rod was painted brown?
- What was the length of the metallic rod?
(a)
Fraction of the metallic rod painted brown
= 1 -
111 -
811=
211(b)
Length of brown part of the metallic rod = 2 u
2 u = 38
1 u = 38 ÷ 2 = 19
Length of the metallic rod
= 11 u
= 11 x 19
= 209 cm
Answer(s): (a)
211; (b) 209 cm