511 of a metallic rod was painted gold.
411 of it was painted blue. The remaining 32 cm of the metallic rod was painted black.
- What fraction of the metallic rod was painted black?
- What was the length of the metallic rod?
(a)
Fraction of the metallic rod painted black
= 1 -
511 -
411=
211(b)
Length of black part of the metallic rod = 2 u
2 u = 32
1 u = 32 ÷ 2 = 16
Length of the metallic rod
= 11 u
= 11 x 16
= 176 cm
Answer(s): (a)
211; (b) 176 cm