711 of a metallic rod was painted blue.
311 of it was painted silver. The remaining 32 cm of the metallic rod was painted green.
- What fraction of the metallic rod was painted green?
- What was the length of the metallic rod?
(a)
Fraction of the metallic rod painted green
= 1 -
711 -
311=
111(b)
Length of green part of the metallic rod = 1 u
1 u = 32
1 u = 32 ÷ 1 = 32
Length of the metallic rod
= 11 u
= 11 x 32
= 352 cm
Answer(s): (a)
111; (b) 352 cm