211 of a metallic rod was painted pink.
811 of it was painted brown. The remaining 47 cm of the metallic rod was painted gold.
- What fraction of the metallic rod was painted gold?
- What was the length of the metallic rod?
(a)
Fraction of the metallic rod painted gold
= 1 -
211 -
811=
111(b)
Length of gold part of the metallic rod = 1 u
1 u = 47
1 u = 47 ÷ 1 = 47
Length of the metallic rod
= 11 u
= 11 x 47
= 517 cm
Answer(s): (a)
111; (b) 517 cm