111 of a metallic rod was painted silver.
611 of it was painted green. The remaining 40 cm of the metallic rod was painted red.
- What fraction of the metallic rod was painted red?
- What was the length of the metallic rod?
(a)
Fraction of the metallic rod painted red
= 1 -
111 -
611=
411(b)
Length of red part of the metallic rod = 4 u
4 u = 40
1 u = 40 ÷ 4 = 10
Length of the metallic rod
= 11 u
= 11 x 10
= 110 cm
Answer(s): (a)
411; (b) 110 cm