311 of a metallic rod was painted blue.
411 of it was painted brown. The remaining 32 cm of the metallic rod was painted red.
- What fraction of the metallic rod was painted red?
- What was the length of the metallic rod?
(a)
Fraction of the metallic rod painted red
= 1 -
311 -
411=
411(b)
Length of red part of the metallic rod = 4 u
4 u = 32
1 u = 32 ÷ 4 = 8
Length of the metallic rod
= 11 u
= 11 x 8
= 88 cm
Answer(s): (a)
411; (b) 88 cm