A stallholder started the day with 510 pears. He sold
310 of the pears and gave
17 of the remainder away. He placed the rest into boxes of 34. How many boxes would he need?
| Sold |
Remainder |
Total |
| 3 u |
7 u |
10 u |
| |
Gave away |
Rest |
|
| 3 u |
1 u |
6 u |
10 u |
Total number of pears = 10 u
10 u = 510
1 u = 510 ÷ 10 = 51
Number of pears that were left
= 6 u
= 6 x 51
= 306
Number of boxes that the stallholder would need
= 306 ÷ 34
= 9
Answer(s): 9
