A stallholder started the day with 770 pears. He sold
27 of the pears and gave
25 of the remainder away. He placed the rest into containers of 33. How many containers would he need?
Sold |
Remainder |
Total |
2 u |
5 u |
7 u |
|
Gave away |
Rest |
|
2 u |
2 u |
3 u |
7 u |
Total number of pears = 7 u
7 u = 770
1 u = 770 ÷ 7 = 110
Number of pears that were left
= 3 u
= 3 x 110
= 330
Number of containers that the stallholder would need
= 330 ÷ 33
= 10
Answer(s): 10