A grocer started the day with 820 pomegranates. He sold
310 of the pomegranates and gave
27 of the remainder away. He placed the rest into boxes of 41. How many boxes would he need?
| Sold |
Remainder |
Total |
| 3 u |
7 u |
10 u |
| |
Gave away |
Rest |
|
| 3 u |
2 u |
5 u |
10 u |
Total number of pomegranates = 10 u
10 u = 820
1 u = 820 ÷ 10 = 82
Number of pomegranates that were left
= 5 u
= 5 x 82
= 410
Number of boxes that the grocer would need
= 410 ÷ 41
= 10
Answer(s): 10
