A fruit seller started the day with 420 pomegranates. He sold
310 of the pomegranates and gave
27 of the remainder away. He placed the rest into boxes of 35. How many boxes would he need?
| Sold |
Remainder |
Total |
| 3 u |
7 u |
10 u |
| |
Gave away |
Rest |
|
| 3 u |
2 u |
5 u |
10 u |
Total number of pomegranates = 10 u
10 u = 420
1 u = 420 ÷ 10 = 42
Number of pomegranates that were left
= 5 u
= 5 x 42
= 210
Number of boxes that the fruit seller would need
= 210 ÷ 35
= 6
Answer(s): 6
