A stallholder started the day with 540 lemons. He sold
49 of the lemons and gave
15 of the remainder away. He placed the rest into containers of 40. How many containers would he need?
| Sold |
Remainder |
Total |
| 4 u |
5 u |
9 u |
| |
Gave away |
Rest |
|
| 4 u |
1 u |
4 u |
9 u |
Total number of lemons = 9 u
9 u = 540
1 u = 540 ÷ 9 = 60
Number of lemons that were left
= 4 u
= 4 x 60
= 240
Number of containers that the stallholder would need
= 240 ÷ 40
= 6
Answer(s): 6
