A store owner started the day with 400 chikoos. He sold
25 of the chikoos and gave
13 of the remainder away. He placed the rest into boxes of 40. How many boxes would he need?
Sold |
Remainder |
Total |
2 u |
3 u |
5 u |
|
Gave away |
Rest |
|
2 u |
1 u |
2 u |
5 u |
Total number of chikoos = 5 u
5 u = 400
1 u = 400 ÷ 5 = 80
Number of chikoos that were left
= 2 u
= 2 x 80
= 160
Number of boxes that the store owner would need
= 160 ÷ 40
= 4
Answer(s): 4