A stallholder started the day with 520 kiwis. He sold
38 of the kiwis and gave
25 of the remainder away. He placed the rest into boxes of 39. How many boxes would he need?
| Sold |
Remainder |
Total |
| 3 u |
5 u |
8 u |
| |
Gave away |
Rest |
|
| 3 u |
2 u |
3 u |
8 u |
Total number of kiwis = 8 u
8 u = 520
1 u = 520 ÷ 8 = 65
Number of kiwis that were left
= 3 u
= 3 x 65
= 195
Number of boxes that the stallholder would need
= 195 ÷ 39
= 5
Answer(s): 5
